What is the integral from 2 to infinity of 8/(x^2) ?

The integral from 2 to infinity of 8/(x^2) is 4

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integral from 2 to infinity of 8/(x^2)

\int_{2}^{\infty} \frac{8}{x ^{2}} d x

4

Solution steps

\int_{2}^{\infty} \frac{8}{x ^{2}} d x

Compute the indefinite integral:

\int \frac{8}{x ^{2}} d x = - \frac{8}{x} + C

Compute the boundaries:

\int_{2}^{\infty} \frac{8}{x ^{2}} d x = 0 - (- 4)

= 0 - (- 4)

Simplify

= 4

\frac{d}{d x} (\frac{( 5 x ^{3} )}{( 1 - 5 x ) ^{4}})

y^{^{''}} - 4 y^{^{'}} + 4 y = e^{- t}

\int 16 x (8 x^{2} + 2)^{6} d x

\frac{d ^{2} y}{d x ^{2}} - y = 2 e^{x} + 6 e^{2 x}

\frac{\partial}{\partial x} (2 x cos (x) cos (y))

What is the integral from 2 to infinity of 8/(x^2) ?
The integral from 2 to infinity of 8/(x^2) is 4