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Popular >

y'+y=y^2

Solution

y^{^{'}} + y = y^{2}

Solution

y = \frac{1}{1 - e ^{t + c_{1}}}

Solution steps

y^{'} (t) + y = y^{2}

Solve separable ODE:

y = \frac{1}{1 - e ^{t + c_{1}}}

y = \frac{1}{1 - e ^{t + c_{1}}}

Popular Examples

integral of (5x^2+2)/(x^4)

\int \frac{5 x ^{2} + 2}{x ^{4}} d x

derivative of (\sqrt[3]{x}-2xe^x/x)

integral from 1 to 2 of 2x^2sqrt(x^3+1)

\int_{1}^{2} 2 x^{2} x^{3} + 1 d x

derivative of (e^x/(sin(2x)))

\frac{d}{d x} (\frac{e ^{x}}{sin ( 2 x )})

integral of x(2x^2+3)^4

\int x (2 x^{2} + 3)^{4} d x

Frequently Asked Questions (FAQ)

What is the solution for y'+y=y^2 ?
The solution for y'+y=y^2 is y= 1/(1-e^{t+c_{1)}}