What is the solution for (xy+y^2+x^2)dx-x^2dy=0 ?

The solution for (xy+y^2+x^2)dx-x^2dy=0 is y=tan(ln(x)+c_{1})x

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(xy+y^2+x^2)dx-x^2dy=0

(x y + y^{2} + x^{2}) d x - x^{2} d y = 0

y = tan (ln (x) + c_{1}) x

Solution steps

(x y + y^{2} + x^{2}) d x - x^{2} d y = 0

Solve using substitution:

y = tan (ln (x) + c_{1}) x

y = tan (ln (x) + c_{1}) x

x \to 0 + lim (\frac{1}{x})

x \to - 4 lim (- (\frac{6}{x + 4}))

\int cos (ln (3 x)) d x

\frac{d}{d x} (\frac{x - a}{b - a})

\frac{5}{x + 9}

What is the solution for (xy+y^2+x^2)dx-x^2dy=0 ?
The solution for (xy+y^2+x^2)dx-x^2dy=0 is y=tan(ln(x)+c_{1})x