What is the integral from 0 to 2 of 3t^5 ?

The integral from 0 to 2 of 3t^5 is 32

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integral from 0 to 2 of 3t^5

\int_{0}^{2} 3 t^{5} d t

32

Solution steps

\int_{0}^{2} 3 t^{5} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{2} t^{5} d t

Apply the Power Rule

: [\frac{t ^{6}}{6}]_{0}^{2}

= 3 [\frac{t ^{6}}{6}]_{0}^{2}

Compute the boundaries:

\frac{32}{3}

= 3 \cdot \frac{32}{3}

Simplify

= 32

x 5 - x^{2}

f (x) = lo g_{8} (x)

\int \frac{k}{x ^{2}} d x

y^{^{''}} + 0.1 y^{^{'}} + y = 0

\frac{\partial}{\partial y} (9 x^{2} + y^{2})

What is the integral from 0 to 2 of 3t^5 ?
The integral from 0 to 2 of 3t^5 is 32