What is the tangent of y=-3cos(x),\at x=(-pi)/4 ?

The tangent of y=-3cos(x),\at x=(-pi)/4 is y=-3/(sqrt(2))x-3/(sqrt(2))-(3pi)/(4sqrt(2))

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tangent of y=-3cos(x),\at x=(-pi)/4

tangent of

y = - 3 cos (x), at x = \frac{- π}{4}

y = - \frac{3}{2} x - \frac{3}{2} - \frac{3 π}{4 2}

Solution steps

Find the tangent point:

(\frac{- π}{4}, - \frac{3}{2})

Find the slope of

y = - 3 cos (x) : \frac{d y}{d x} = 3 sin (x)

Compute the slope of

y = - 3 cos (x)

x = \frac{- π}{4} : m = - \frac{3}{2}

Find the line with slope m=

- \frac{3}{2}

and passing through

(\frac{- π}{4}, - \frac{3}{2}) : y = - \frac{3}{2} x - \frac{3}{2} - \frac{3 π}{4 2}

y = - \frac{3}{2} x - \frac{3}{2} - \frac{3 π}{4 2}

3 x + 1, x + 1

\int \frac{sin ^{7} ( 9 x )}{cos ^{4} ( 9 x )} d x

\int x^{3} x^{2} + 4 d x

\frac{d y}{d x} - 2 x y = 15 x^{2} e^{x^{2}}

\frac{\partial}{\partial x} (x y (2 + x) (y - 3))

What is the tangent of y=-3cos(x),\at x=(-pi)/4 ?
The tangent of y=-3cos(x),\at x=(-pi)/4 is y=-3/(sqrt(2))x-3/(sqrt(2))-(3pi)/(4sqrt(2))