What is the derivative of n^x ?

The derivative of n^x is n^xln(n)

What is the first derivative of n^x ?

The first derivative of n^x is n^xln(n)

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\frac{d}{d x} (n^{x})

n^{x} ln (n)

Solution steps

\frac{d}{d x} (n^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= n^{x} ln (n)

y^{^{''}} + 6 y^{^{'}} + 9 y = 0

\frac{d y}{d t} - (\frac{3}{t}) y = 2 t^{3} e^{2 t}, y (1) = 0

\int \frac{x + 5}{x - 2} d x

\int 6 θ cos (θ) d θ

\frac{x + 2}{4 x - 3}