What is the derivative of f(x)=(x^3)/3+3/(x^3) ?

The derivative of f(x)=(x^3)/3+3/(x^3) is x^2-9/(x^4)

What is the first derivative of f(x)=(x^3)/3+3/(x^3) ?

The first derivative of f(x)=(x^3)/3+3/(x^3) is x^2-9/(x^4)

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derivative of

f (x) = \frac{x ^{3}}{3} + \frac{3}{x ^{3}}

x^{2} - \frac{9}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{3} + \frac{3}{x ^{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{3}) + \frac{d}{d x} (\frac{3}{x ^{3}})

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d}{d x} (\frac{3}{x ^{3}}) = - \frac{9}{x ^{4}}

= x^{2} - \frac{9}{x ^{4}}

\int x 5^{- x} d x

\int x (2 x + 5) d x

\frac{\partial}{\partial x} (8 e^{x y})

\frac{d y}{d t} = - y^{2}

5 x ln (3 x) - 5 x

What is the derivative of f(x)=(x^3)/3+3/(x^3) ?
The derivative of f(x)=(x^3)/3+3/(x^3) is x^2-9/(x^4)
What is the first derivative of f(x)=(x^3)/3+3/(x^3) ?
The first derivative of f(x)=(x^3)/3+3/(x^3) is x^2-9/(x^4)