What is the integral of 1/(\sqrt[7]{x^2)} ?

The integral of 1/(\sqrt[7]{x^2)} is 7/5 x^{5/7}+C

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integral of 1/(\sqrt[7]{x^2)}

\frac{7}{5} x^{\frac{5}{7}} + C

Solution steps

assuming

x \geq 0

= \int \frac{1}{x ^{\frac{2}{7}}} d x

Apply the Power Rule

: \frac{7}{5} x^{\frac{5}{7}}

= \frac{7}{5} x^{\frac{5}{7}}

Add a constant to the solution

= \frac{7}{5} x^{\frac{5}{7}} + C

\int \frac{( 2 x ^{2} - 1 )}{x - x ^{3}} d x

\frac{d}{d x} (sin (tan (x^{5})))

\frac{d y}{d x} = 3 - 0.0003 y

\frac{d}{d x} (3 x^{2} - 6 x + 5)

What is the integral of 1/(\sqrt[7]{x^2)} ?
The integral of 1/(\sqrt[7]{x^2)} is 7/5 x^{5/7}+C