What is the solution for (dy)/(dx)-(x+1)y=xy^2 ?

The solution for (dy)/(dx)-(x+1)y=xy^2 is y=(e^{(x^2+2x)/2})/(integral of-e^{(x^2)/2+x)x}

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(dy)/(dx)-(x+1)y=xy^2

\frac{d y}{d x} - (x + 1) y = x y^{2}

y = \frac{e ^{\frac{x ^{2} + 2 x}{2}}}{\int - e ^{\frac{x ^{2}}{2} + x} x d x}

Solution steps

\frac{d y}{d x} - (x + 1) y = x y^{2}

Solve Bernoulli ODE:

y = \frac{e ^{\frac{x ^{2} + 2 x}{2}}}{\int - e ^{\frac{x ^{2}}{2} + x} x d x}

y = \frac{e ^{\frac{x ^{2} + 2 x}{2}}}{\int - e ^{\frac{x ^{2}}{2} + x} x d x}

7 t y^{^{'}} + y = 0, y (1) = 1

\int 5 x 2 x^{2} + 3 d x

y = \frac{2}{x}, y = 8 x, y = \frac{1}{8 x}

x \frac{d y}{d x} - y = x^{2} + y^{2}

f (x) = 2 x 2 x^{2} + 4

What is the solution for (dy)/(dx)-(x+1)y=xy^2 ?
The solution for (dy)/(dx)-(x+1)y=xy^2 is y=(e^{(x^2+2x)/2})/(integral of-e^{(x^2)/2+x)x}