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Popular >

y^'=(3t+1)^2

Solution

y^{^{'}} = (3 t + 1)^{2}

Solution

y = 3 t^{3} + 3 t^{2} + t + c_{1}

Solution steps

y^{'} (t) = (3 t + 1)^{2}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int (3 t + 1)^{2} d t

\int (3 t + 1)^{2} d t = 3 t^{3} + 3 t^{2} + t + c_{1}

y = 3 t^{3} + 3 t^{2} + t + c_{1}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=(3t+1)^2 ?
The solution for y^'=(3t+1)^2 is y=3t^3+3t^2+t+c_{1}