What is the derivative of e^{2x}+ln(2x) ?

The derivative of e^{2x}+ln(2x) is e^{2x}*2+1/x

What is the first derivative of e^{2x}+ln(2x) ?

The first derivative of e^{2x}+ln(2x) is e^{2x}*2+1/x

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\frac{d}{d x} (e^{2 x} + ln (2 x))

e^{2 x} \cdot 2 + \frac{1}{x}

Solution steps

\frac{d}{d x} (e^{2 x} + ln (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{2 x}) + \frac{d}{d x} (ln (2 x))

\frac{d}{d x} (e^{2 x}) = e^{2 x} \cdot 2

\frac{d}{d x} (ln (2 x)) = \frac{1}{x}

= e^{2 x} \cdot 2 + \frac{1}{x}

\int 3^{x} - 5 sin (2 x) d x

n = 0 \sum \infty (n + 1)^{2}

\frac{\partial}{\partial x} (\frac{x ^{2} + y}{y ^{2}})

y^{^{''}} - 4 y^{^{'}} + 8 y = 0

f (x) = arcsin (\frac{x}{4})

What is the derivative of e^{2x}+ln(2x) ?
The derivative of e^{2x}+ln(2x) is e^{2x}*2+1/x
What is the first derivative of e^{2x}+ln(2x) ?
The first derivative of e^{2x}+ln(2x) is e^{2x}*2+1/x