What is the tangent of y=x^4+2x^2-x,(1,2) ?

The tangent of y=x^4+2x^2-x,(1,2) is y=7x-5

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tangent of y=x^4+2x^2-x,(1,2)

tangent of

y = x^{4} + 2 x^{2} - x, (1, 2)

y = 7 x - 5

Solution steps

Find the slope of

y = x^{4} + 2 x^{2} - x : \frac{d y}{d x} = 4 x^{3} + 4 x - 1

Compute the slope of

y = x^{4} + 2 x^{2} - x

(1, 2) : m = 7

Find the line with slope m=

7

and passing through

(1, 2) : y = 7 x - 5

y = 7 x - 5

\int 16 x ln (6 x) d x

x y^{^{'}} + y = 8 x y^{2}

(4 x + 5)^{- 1}

n = 0 \sum \infty \frac{3}{4 ^{n}}

\frac{d}{d x} (x^{2} π)

What is the tangent of y=x^4+2x^2-x,(1,2) ?
The tangent of y=x^4+2x^2-x,(1,2) is y=7x-5