What is the first (e^{x/2})^' ?

The first (e^{x/2})^' is e^{x/2} 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(e^{x/2})^'

(e^{\frac{x}{2}})^{^{'}}

e^{\frac{x}{2}} \frac{1}{2}

Solution steps

(e^{\frac{x}{2}})^{'}

Apply the chain rule:

e^{\frac{x}{2}} (\frac{x}{2})^{'}

= e^{\frac{x}{2}} (\frac{x}{2})^{'}

(\frac{x}{2})^{'} = \frac{1}{2}

= e^{\frac{x}{2}} \frac{1}{2}

x \to 2 + lim (\frac{6}{x - 2})

\int \frac{28 s ^{3}}{8 - s ^{4}} d s

tan (π x)

x \to 0 lim (\frac{4 x}{4 + x - 4 - x})

\int \frac{2 x - 4}{x ^{2} + 4} d x