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Popular >

yy^'=t^2,y(0)=2

Solution

y y^{^{'}} = t^{2}, y (0) = 2

Solution

y = \frac{2 t ^{3}}{3} + 4

Solution steps

y y^{'} (t) = t^{2}

Solve separable ODE:

y = \frac{2 t ^{3}}{3} + 4

y = \frac{2 t ^{3}}{3} + 4

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\int_{0}^{4} (y - y + 2) d y

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t \to - 2 lim (\frac{t ^{2} - 4}{t + 2})

(\partial)/(\partial x)(7xe^{xy})

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Frequently Asked Questions (FAQ)

What is the solution for yy^'=t^2,y(0)=2 ?
The solution for yy^'=t^2,y(0)=2 is y=sqrt((2t^3)/3+4)