What is the derivative of (x+9)/(x^2-7x+1) ?

The derivative of (x+9)/(x^2-7x+1) is (-x^2-18x+64)/((x^2-7x+1)^2)

What is the first derivative of (x+9)/(x^2-7x+1) ?

The first derivative of (x+9)/(x^2-7x+1) is (-x^2-18x+64)/((x^2-7x+1)^2)

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derivative of

\frac{x + 9}{x ^{2} - 7 x + 1}

\frac{- x ^{2} - 18 x + 64}{( x ^{2} - 7 x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x + 9}{x ^{2} - 7 x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x + 9 ) ( x ^{2} - 7 x + 1 ) - \frac{d}{d x} ( x ^{2} - 7 x + 1 ) ( x + 9 )}{( x ^{2} - 7 x + 1 ) ^{2}}

\frac{d}{d x} (x + 9) = 1

\frac{d}{d x} (x^{2} - 7 x + 1) = 2 x - 7

= \frac{1 \cdot ( x ^{2} - 7 x + 1 ) - ( 2 x - 7 ) ( x + 9 )}{( x ^{2} - 7 x + 1 ) ^{2}}

Simplify

\frac{1 \cdot ( x ^{2} - 7 x + 1 ) - ( 2 x - 7 ) ( x + 9 )}{( x ^{2} - 7 x + 1 ) ^{2}} : \frac{- x ^{2} - 18 x + 64}{( x ^{2} - 7 x + 1 ) ^{2}}

= \frac{- x ^{2} - 18 x + 64}{( x ^{2} - 7 x + 1 ) ^{2}}

\frac{\partial}{\partial x} (7 x^{5 y})

\frac{d}{d x} (\frac{8}{∣ x - 2 ∣ ^{3}})

\int (2 x^{2} + 2 x - 3)^{10} \cdot (2 x + 1) d x

\frac{d}{d x} (\frac{9 - x ^{2} - y ^{2}}{x + z})

\frac{d}{d x} (cos (7 π x))

What is the derivative of (x+9)/(x^2-7x+1) ?
The derivative of (x+9)/(x^2-7x+1) is (-x^2-18x+64)/((x^2-7x+1)^2)
What is the first derivative of (x+9)/(x^2-7x+1) ?
The first derivative of (x+9)/(x^2-7x+1) is (-x^2-18x+64)/((x^2-7x+1)^2)