en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area f(x)=2x+3,[-1,2]

Solution

area

f (x) = 2 x + 3, [- 1, 2]

Solution

12

Solution steps

Apply the area formula:

\int_{- 1}^{2} ∣ 2 x + 3 ∣ d x

Solve

\int_{- 1}^{2} ∣ 2 x + 3 ∣ d x : 12

The area is:

= 12

Popular Examples

integral of (sin(2u)-cos(3u))^2

\int (sin (2 u) - cos (3 u))^{2} d u

derivative of (-2x)/((x^2-1)^2)derivative of

\frac{- 2 x}{( x ^{2} - 1 ) ^{2}}

(cos(3x))y^'-3(tan(3x))y=2(sec(3x))

(cos (3 x)) y^{^{'}} - 3 (tan (3 x)) y = 2 (sec (3 x))

f (t) = 4 t

integral of sin^{1/2}(x)cos^3(x)

\int sin^{\frac{1}{2}} (x) cos^{3} (x) d x

Frequently Asked Questions (FAQ)

What is area f(x)=2x+3,[-1,2] ?
The answer to area f(x)=2x+3,[-1,2] is 12