What is the integral from 3 to infinity of e^{-4x} ?

The integral from 3 to infinity of e^{-4x} is 1/(4e^{12)}

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integral from 3 to infinity of e^{-4x}

\int_{3}^{\infty} e^{- 4 x} d x

\frac{1}{4 e ^{12}}

Decimal Notation

1.53605 E - 6

Solution steps

\int_{3}^{\infty} e^{- 4 x} d x

Compute the indefinite integral:

\int e^{- 4 x} d x = - \frac{1}{4} e^{- 4 x} + C

Compute the boundaries:

\int_{3}^{\infty} e^{- 4 x} d x = 0 - (- \frac{1}{4 e ^{12}})

= 0 - (- \frac{1}{4 e ^{12}})

Simplify

= \frac{1}{4 e ^{12}}

\frac{d y}{d x} = \frac{2 y + x ^{2} - y ^{2}}{2 x}

\frac{3}{s + 1}

\int \frac{sec ^{6} ( x )}{tan ^{3} ( x )} d x

x \to 0 - lim (e^{\frac{3}{x}})

\frac{\partial}{\partial x} (9)

What is the integral from 3 to infinity of e^{-4x} ?
The integral from 3 to infinity of e^{-4x} is 1/(4e^{12)}