What is the derivative of (x^2)/(x-9) ?

The derivative of (x^2)/(x-9) is (x^2-18x)/((x-9)^2)

What is the first derivative of (x^2)/(x-9) ?

The first derivative of (x^2)/(x-9) is (x^2-18x)/((x-9)^2)

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derivative of

\frac{x ^{2}}{x - 9}

\frac{x ^{2} - 18 x}{( x - 9 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{x - 9})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( x - 9 ) - \frac{d}{d x} ( x - 9 ) x ^{2}}{( x - 9 ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x - 9) = 1

= \frac{2 x ( x - 9 ) - 1 \cdot x ^{2}}{( x - 9 ) ^{2}}

Simplify

\frac{2 x ( x - 9 ) - 1 \cdot x ^{2}}{( x - 9 ) ^{2}} : \frac{x ^{2} - 18 x}{( x - 9 ) ^{2}}

= \frac{x ^{2} - 18 x}{( x - 9 ) ^{2}}

x^{\frac{1}{3}}

(a - 7 x) (a + 7 x)

(x^{3} + 3 y) d x - x d y = 0

\frac{d y}{d x} - 4 y = - 4 y^{2}

\int \frac{e ^{x}}{( e ^{x} - 9 ) ( e ^{2 x} + 1 )} d x

What is the derivative of (x^2)/(x-9) ?
The derivative of (x^2)/(x-9) is (x^2-18x)/((x-9)^2)
What is the first derivative of (x^2)/(x-9) ?
The first derivative of (x^2)/(x-9) is (x^2-18x)/((x-9)^2)