What is the derivative of 5/(x+4) ?

The derivative of 5/(x+4) is -5/((x+4)^2)

What is the first derivative of 5/(x+4) ?

The first derivative of 5/(x+4) is -5/((x+4)^2)

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\frac{d}{d x} (\frac{5}{x + 4})

- \frac{5}{( x + 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{5}{x + 4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (\frac{1}{x + 4})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 5 \frac{d}{d x} ((x + 4)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 4 ) ^{2}} \frac{d}{d x} (x + 4)

= - \frac{1}{( x + 4 ) ^{2}} \frac{d}{d x} (x + 4)

\frac{d}{d x} (x + 4) = 1

= 5 (- \frac{1}{( x + 4 ) ^{2}} \cdot 1)

Simplify

5 (- \frac{1}{( x + 4 ) ^{2}} \cdot 1) : - \frac{5}{( x + 4 ) ^{2}}

= - \frac{5}{( x + 4 ) ^{2}}

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2}}{9 + 8 x})

\int_{0}^{2} - 2 x^{2} - 4 d x

y = \frac{1}{2} x, y = \frac{6}{x}

\int \frac{t ^{3}}{1 + t} d t

\int cos^{4} (x) sin^{5} (x) d x

What is the derivative of 5/(x+4) ?
The derivative of 5/(x+4) is -5/((x+4)^2)
What is the first derivative of 5/(x+4) ?
The first derivative of 5/(x+4) is -5/((x+4)^2)