What is the limit as x approaches 0 of (1-cos(4x))/x ?

The limit as x approaches 0 of (1-cos(4x))/x is 0

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limit as x approaches 0 of (1-cos(4x))/x

x \to 0 lim (\frac{1 - cos ( 4 x )}{x})

0

Solution steps

x \to 0 lim (\frac{1 - cos ( 4 x )}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{4 sin ( 4 x )}{1})

= x \to 0 lim (\frac{4 sin ( 4 x )}{1})

Plug in the value

x = 0

= \frac{4 sin ( 4 \cdot 0 )}{1}

Simplify

\frac{4 sin ( 4 \cdot 0 )}{1} : 0

= 0

\int 6 y - x - 4 d y

x \to 2 lim (1 - x)

\int_{0}^{2} 6 x^{3} x^{2} + 4 d x

f (x) = - x^{2} + 2 x + 4, at x = 4

\int_{0}^{1} \frac{1}{e ^{3 x}} d x

What is the limit as x approaches 0 of (1-cos(4x))/x ?
The limit as x approaches 0 of (1-cos(4x))/x is 0