What is the sum from n=0 to infinity of (e^n)/(pi^n) ?

The sum from n=0 to infinity of (e^n)/(pi^n) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of (e^n)/(pi^n)

n = 0 \sum \infty \frac{e ^{n}}{π ^{n}}

converges

Solution steps

n = 0 \sum \infty \frac{e ^{n}}{π ^{n}}

Apply exponent rule:

\frac{a ^{c}}{b ^{c}} = (\frac{a}{b})^{c}

= n = 0 \sum \infty (\frac{e}{π})^{n}

Apply Series Ratio Test:

converges

= converges

\frac{d}{d x} (3 (4 e^{2 x} x + 4 e^{2 x}))

\int \frac{x}{10 - x ^{2}} d x

n = 1 \sum \infty \frac{1}{( 2 n - 1 )}

\int 7 sin^{4} (x) cos^{2} (x) d x

\frac{\partial}{\partial x} (63 x^{8} y^{6} - 48 x^{7} y^{5})

What is the sum from n=0 to infinity of (e^n)/(pi^n) ?
The sum from n=0 to infinity of (e^n)/(pi^n) is converges