What is (\partial)/(\partial y)(2x^2+3y^2) ?

The answer to (\partial)/(\partial y)(2x^2+3y^2) is 6y

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(\partial)/(\partial y)(2x^2+3y^2)

\frac{\partial}{\partial y} (2 x^{2} + 3 y^{2})

6 y

Solution steps

\frac{\partial}{\partial y} (2 x^{2} + 3 y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x^{2}) + \frac{\partial}{\partial y} (3 y^{2})

\frac{\partial}{\partial y} (2 x^{2}) = 0

\frac{\partial}{\partial y} (3 y^{2}) = 6 y

= 0 + 6 y

Simplify

= 6 y

\frac{d}{d x} (1700 e^{x})

\int (6 x^{2} y - 3 x y) d y

\int 3 sin (2 θ) d θ

3 x^{4} + 9 x^{3} + 11

\int \frac{x ( x + 1 ) ^{2}}{x} d x

What is (\partial)/(\partial y)(2x^2+3y^2) ?
The answer to (\partial)/(\partial y)(2x^2+3y^2) is 6y