What is the derivative of 2x^2-5x-3 ?

The derivative of 2x^2-5x-3 is 4x-5

What is the first derivative of 2x^2-5x-3 ?

The first derivative of 2x^2-5x-3 is 4x-5

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derivative of

2 x^{2} - 5 x - 3

4 x - 5

Solution steps

\frac{d}{d x} (2 x^{2} - 5 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (5 x) - \frac{d}{d x} (3)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (3) = 0

= 4 x - 5 - 0

Simplify

= 4 x - 5

\int_{- 3}^{x} (t + 3) d t

\int \frac{cos ( x )}{sin ^{5} ( x )} d x

f (x) = \frac{x ^{3} - 3 x ^{2} + 4}{x ^{2}}

\frac{d}{d x} (e^{x} \cdot cos (x))

\frac{\partial}{\partial x} (6 x e^{x + y})

What is the derivative of 2x^2-5x-3 ?
The derivative of 2x^2-5x-3 is 4x-5
What is the first derivative of 2x^2-5x-3 ?
The first derivative of 2x^2-5x-3 is 4x-5