What is the limit as x approaches 2 of 1/(4-x^2) ?

The limit as x approaches 2 of 1/(4-x^2) is diverges

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limit as x approaches 2 of 1/(4-x^2)

x \to 2 lim (\frac{1}{4 - x ^{2}})

diverges

Solution steps

x \to 2 lim (\frac{1}{4 - x ^{2}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 2 + lim (\frac{1}{4 - x ^{2}}) = - \infty

x \to 2 - lim (\frac{1}{4 - x ^{2}}) = \infty

= diverges

\int \frac{x ^{4}}{( 2 - x ^{5} ) ^{4}} d x

y = \frac{4 x ^{2} + 6 x + 2}{x}

\int e^{2 x} \cdot e^{- x} d x

\int_{1}^{2} \frac{( x - 4 )}{x ^{2}} d x

f (x) = 2 x^{3} - 2 x, (1, 0)

What is the limit as x approaches 2 of 1/(4-x^2) ?
The limit as x approaches 2 of 1/(4-x^2) is diverges