What is the limit as x approaches 0 of (sin(6x))/2 ?

The limit as x approaches 0 of (sin(6x))/2 is 0

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limit as x approaches 0 of (sin(6x))/2

x \to 0 lim (\frac{sin ( 6 x )}{2})

0

Solution steps

x \to 0 lim (\frac{sin ( 6 x )}{2})

Plug in the value

x = 0

= \frac{sin ( 6 \cdot 0 )}{2}

Simplify

\frac{sin ( 6 \cdot 0 )}{2} : 0

= 0

\int \frac{x}{3 x ^{2} - 5} d x

\frac{d y}{d x} = 3 x y^{2}

(x - y^{4} + y^{2} sin (x)) d x = (4 x y^{3} + 2 y cos (x)) d y

y^{^{''}} + 4 y = 7 sin (2 x)

5 x y (\frac{d y}{d x}) = 2

What is the limit as x approaches 0 of (sin(6x))/2 ?
The limit as x approaches 0 of (sin(6x))/2 is 0