What is the derivative of 3/(t^4) ?

The derivative of 3/(t^4) is -(12)/(t^5)

What is the first derivative of 3/(t^4) ?

The first derivative of 3/(t^4) is -(12)/(t^5)

Popular >

derivative of

\frac{3}{t ^{4}}

- \frac{12}{t ^{5}}

Solution steps

\frac{d}{d t} (\frac{3}{t ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d t} (\frac{1}{t ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d t} (t^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 (- 4 t^{- 4 - 1})

Simplify

3 (- 4 t^{- 4 - 1}) : - \frac{12}{t ^{5}}

= - \frac{12}{t ^{5}}

\frac{\partial}{\partial u} (uv - 1)

\frac{2 s}{( s - 1 ) ( s ^{2} + 25 )}

\frac{\partial}{\partial y} (e^{- y} (x^{2} + y^{2}))

x (\frac{d y}{d x}) = x^{2} - 4

f (x) = (5 x^{2} - 7 x) e^{x}

What is the derivative of 3/(t^4) ?
The derivative of 3/(t^4) is -(12)/(t^5)
What is the first derivative of 3/(t^4) ?
The first derivative of 3/(t^4) is -(12)/(t^5)