What is the solution for ydx+(ycos(x/y)-x)dy=0 ?

The solution for ydx+(ycos(x/y)-x)dy=0 is y= x/(ln(x)+c_{1)}

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ydx+(ycos(x/y)-x)dy=0

y d x + (y cos (\frac{x}{y}) - x) d y = 0

y = \frac{x}{ln ( x ) + c _{1}}

Solution steps

y d x + (y cos (\frac{x}{y}) - x) d y = 0

Solve using substitution:

y = \frac{x}{ln ( x ) + c _{1}}

y = \frac{x}{ln ( x ) + c _{1}}

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What is the solution for ydx+(ycos(x/y)-x)dy=0 ?
The solution for ydx+(ycos(x/y)-x)dy=0 is y= x/(ln(x)+c_{1)}