What is (\partial)/(\partial x)(cos(x^2y)) ?

The answer to (\partial)/(\partial x)(cos(x^2y)) is -sin(x^2y)*2yx

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(\partial)/(\partial x)(cos(x^2y))

\frac{\partial}{\partial x} (cos (x^{2} y))

- sin (x^{2} y) \cdot 2 y x

Solution steps

\frac{\partial}{\partial x} (cos (x^{2} y))

Treat

y

as a constant

Apply the chain rule:

- sin (x^{2} y) \frac{\partial}{\partial x} (x^{2} y)

= - sin (x^{2} y) \frac{\partial}{\partial x} (x^{2} y)

\frac{\partial}{\partial x} (x^{2} y) = 2 y x

= - sin (x^{2} y) \cdot 2 y x

\int - 2 x + 18 x^{2} - 4 x^{3} + 18 d x

x \to 0 + lim (e^{- \frac{2}{x}})

\frac{\partial}{\partial x} (\frac{5 x}{y})

[x + (x + sin^{2} (x))^{7}]^{6}

e^{- 1} sin (t)

What is (\partial)/(\partial x)(cos(x^2y)) ?
The answer to (\partial)/(\partial x)(cos(x^2y)) is -sin(x^2y)*2yx