What is the integral of arctan(5x-1) ?

The integral of arctan(5x-1) is 1/10 (2arctan(5x-1)(5x-1)-ln|25x^2-10x+2|)+C

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integral of arctan(5x-1)

\int arctan (5 x - 1) d x

\frac{1}{10} (2 arctan (5 x - 1) (5 x - 1) - ln 25 x^{2} - 10 x + 2) + C

Solution steps

\int arctan (5 x - 1) d x

Apply u-substitution

: \int arctan (u) \frac{1}{5} d u

= \int arctan (u) \frac{1}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int arctan (u) d u

Apply Integration By Parts

: u arctan (u) - \int \frac{u}{u ^{2} + 1} d u

= \frac{1}{5} (u arctan (u) - \int \frac{u}{u ^{2} + 1} d u)

\int \frac{u}{u ^{2} + 1} d u = \frac{1}{2} ln u^{2} + 1

= \frac{1}{5} (u arctan (u) - \frac{1}{2} ln u^{2} + 1)

Substitute back

u = 5 x - 1

= \frac{1}{5} ((5 x - 1) arctan (5 x - 1) - \frac{1}{2} ln (5 x - 1)^{2} + 1)

Simplify

\frac{1}{5} ((5 x - 1) arctan (5 x - 1) - \frac{1}{2} ln (5 x - 1)^{2} + 1) : \frac{1}{10} (2 arctan (5 x - 1) (5 x - 1) - ln 25 x^{2} - 10 x + 2)

= \frac{1}{10} (2 arctan (5 x - 1) (5 x - 1) - ln 25 x^{2} - 10 x + 2)

Add a constant to the solution

= \frac{1}{10} (2 arctan (5 x - 1) (5 x - 1) - ln 25 x^{2} - 10 x + 2) + C

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What is the integral of arctan(5x-1) ?
The integral of arctan(5x-1) is 1/10 (2arctan(5x-1)(5x-1)-ln|25x^2-10x+2|)+C