What is (\partial)/(\partial x)(sin(3x+2y+z)) ?

The answer to (\partial)/(\partial x)(sin(3x+2y+z)) is cos(3x+2y+z)*3

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(\partial)/(\partial x)(sin(3x+2y+z))

\frac{\partial}{\partial x} (sin (3 x + 2 y + z))

cos (3 x + 2 y + z) \cdot 3

Solution steps

\frac{\partial}{\partial x} (sin (3 x + 2 y + z))

Treat

y, z

as constants

Apply the chain rule:

cos (3 x + 2 y + z) \frac{\partial}{\partial x} (3 x + 2 y + z)

= cos (3 x + 2 y + z) \frac{\partial}{\partial x} (3 x + 2 y + z)

\frac{\partial}{\partial x} (3 x + 2 y + z) = 3

= cos (3 x + 2 y + z) \cdot 3

y^{^{''}} - 2 \cdot y = 981, y^{^{'}} (0) = 0, y (0) = 0

\frac{\partial}{\partial x} (\frac{( 3 x + y )}{z})

\frac{\partial}{\partial x} (sin (\frac{x - y}{x + y}))

\int sin^{2} (8 x) cos^{2} (8 x) d x

\frac{d y}{d x} = - \frac{x y}{ln ( y )}

What is (\partial)/(\partial x)(sin(3x+2y+z)) ?
The answer to (\partial)/(\partial x)(sin(3x+2y+z)) is cos(3x+2y+z)*3