What is the integral of-cos(x)3x^2 ?

The integral of-cos(x)3x^2 is -3(x^2sin(x)-2(-xcos(x)+sin(x)))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of-cos(x)3x^2

\int - cos (x) 3 x^{2} d x

- 3 (x^{2} sin (x) - 2 (- x cos (x) + sin (x))) + C

Solution steps

\int - cos (x) \cdot 3 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 3 \cdot \int cos (x) x^{2} d x

Apply Integration By Parts

: x^{2} sin (x) - \int 2 x sin (x) d x

= - 3 (x^{2} sin (x) - \int 2 x sin (x) d x)

\int 2 x sin (x) d x = 2 (- x cos (x) + sin (x))

= - 3 (x^{2} sin (x) - 2 (- x cos (x) + sin (x)))

Add a constant to the solution

= - 3 (x^{2} sin (x) - 2 (- x cos (x) + sin (x))) + C

\int \frac{1}{3 x + 6} d x

x \to 1 - lim (\frac{1}{x - 1})

- 5 x x

\int - 4 cos (\frac{x}{2}) + 5 d x

(x + 1) y^{^{'}} + (x + 2) y = 2 x e^{- 2}

What is the integral of-cos(x)3x^2 ?
The integral of-cos(x)3x^2 is -3(x^2sin(x)-2(-xcos(x)+sin(x)))+C