What is the integral from 0 to 1 of (33)/(x^5) ?

The integral from 0 to 1 of (33)/(x^5) is diverges

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integral from 0 to 1 of (33)/(x^5)

\int_{0}^{1} \frac{33}{x ^{5}} d x

diverges

Solution steps

\int_{0}^{1} \frac{33}{x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 33 \cdot \int_{0}^{1} \frac{1}{x ^{5}} d x

Apply the Power Rule

: [- \frac{1}{4 x ^{4}}]_{0}^{1}

= 33 [- \frac{1}{4 x ^{4}}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

\int e^{- (s - a) t} d t

(3 + x^{5})^{\frac{2}{3}}

\frac{d}{d x} (π \cdot x)

\frac{d}{d t} (cos (t^{2}))

\frac{d}{d x} (\frac{π}{x})

What is the integral from 0 to 1 of (33)/(x^5) ?
The integral from 0 to 1 of (33)/(x^5) is diverges