What is the solution for y^'+ycos(x)=5cos(x) ?

The solution for y^'+ycos(x)=5cos(x) is y=e^{-sin(x)+c_{1}}+5

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y^'+ycos(x)=5cos(x)

y^{^{'}} + y cos (x) = 5 cos (x)

y = e^{- s i n (x) + c_{1}} + 5

Solution steps

y^{'} (x) + y cos (x) = 5 cos (x)

Solve separable ODE:

y = e^{- s i n (x) + c_{1}} + 5

y = e^{- s i n (x) + c_{1}} + 5

\int sin^{4} (y) cos^{4} (y) d y

f (x) = sin (π x)

x \to 5 lim (5 - x^{2})

\frac{d}{d x} (\frac{2 x ^{2} - 4}{( x + 4 ) ^{2}})

y^{^{'''}} - y^{^{''}} - y^{^{'}} + y = 2 e^{- x} + 3

What is the solution for y^'+ycos(x)=5cos(x) ?
The solution for y^'+ycos(x)=5cos(x) is y=e^{-sin(x)+c_{1}}+5