What is the integral of sin(3x)+cos(5x) ?

The integral of sin(3x)+cos(5x) is -1/3 cos(3x)+1/5 sin(5x)+C

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integral of sin(3x)+cos(5x)

\int sin (3 x) + cos (5 x) d x

- \frac{1}{3} cos (3 x) + \frac{1}{5} sin (5 x) + C

Solution steps

\int sin (3 x) + cos (5 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sin (3 x) d x + \int cos (5 x) d x

\int sin (3 x) d x = - \frac{1}{3} cos (3 x)

\int cos (5 x) d x = \frac{1}{5} sin (5 x)

= - \frac{1}{3} cos (3 x) + \frac{1}{5} sin (5 x)

Add a constant to the solution

= - \frac{1}{3} cos (3 x) + \frac{1}{5} sin (5 x) + C

y = e^{- \frac{7}{t ^{2}}}

y = - 3 x + 2

\frac{3 s + 3}{s ^{2} - 9}

- x^{4} - x^{2}

\frac{\partial}{\partial x} (2 (x + c))

What is the integral of sin(3x)+cos(5x) ?
The integral of sin(3x)+cos(5x) is -1/3 cos(3x)+1/5 sin(5x)+C