What is laplacetransform 4e^{-3t} ?

The answer to laplacetransform 4e^{-3t} is 4/(s+3)

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laplacetransform 4e^{-3t}

laplace transform

4 e^{- 3 t}

\frac{4}{s + 3}

Solution steps

L {4 e^{- 3 t}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 4 L {e^{- 3 t}}

L {e^{- 3 t}} : \frac{1}{s + 3}

= 4 \cdot \frac{1}{s + 3}

Refine

4 \frac{1}{s + 3} : \frac{4}{s + 3}

= \frac{4}{s + 3}

\frac{d y}{d x} + 5 y = e^{x} y^{- 4}

\int \frac{7}{3 x ^{2} + x + 2} d x

\int 3 t^{3} d t

x y^{2} d x - x^{2} y^{2} d y = 0

\frac{d}{d x} (e^{\frac{( - x ^{2} )}{2}})

What is laplacetransform 4e^{-3t} ?
The answer to laplacetransform 4e^{-3t} is 4/(s+3)