What is the derivative of y= 3/(sin(2x)) ?

The derivative of y= 3/(sin(2x)) is -6cot(2x)csc(2x)

What is the first derivative of y= 3/(sin(2x)) ?

The first derivative of y= 3/(sin(2x)) is -6cot(2x)csc(2x)

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derivative of

y = \frac{3}{sin ( 2 x )}

- 6 cot (2 x) csc (2 x)

Solution steps

\frac{d}{d x} (\frac{3}{sin ( 2 x )})

Simplify

\frac{3}{sin ( 2 x )} : 3 csc (2 x)

= \frac{d}{d x} (3 csc (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (csc (2 x))

Apply the chain rule:

- cot (2 x) csc (2 x) \frac{d}{d x} (2 x)

= - cot (2 x) csc (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 3 (- cot (2 x) csc (2 x) \cdot 2)

Simplify

= - 6 cot (2 x) csc (2 x)

x \to 1 lim (\frac{( x + 3 )}{2})

\int (a x + b)^{n} d x

\int 27 - 6 x - x^{2} d x

\frac{d}{d x} (e^{3 x} \cdot cos (2 x))

\frac{d y}{d x} + y^{5} x + 9 y = 0

What is the derivative of y= 3/(sin(2x)) ?
The derivative of y= 3/(sin(2x)) is -6cot(2x)csc(2x)
What is the first derivative of y= 3/(sin(2x)) ?
The first derivative of y= 3/(sin(2x)) is -6cot(2x)csc(2x)