What is the derivative of sqrt(x)+\sqrt[9]{x} ?

The derivative of sqrt(x)+\sqrt[9]{x} is 1/(2sqrt(x))+1/(9x^{8/9)}

What is the first derivative of sqrt(x)+\sqrt[9]{x} ?

The first derivative of sqrt(x)+\sqrt[9]{x} is 1/(2sqrt(x))+1/(9x^{8/9)}

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derivative of

\frac{1}{2 x} + \frac{1}{9 x ^{\frac{8}{9}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{1}{2 x} + \frac{1}{9 x ^{\frac{8}{9}}}

\int (11 - x) d x

x \to 5 + lim (\frac{3}{x - 5})

\int_{0}^{\frac{π}{12}} 6 tan (3 x) d x

\frac{\partial}{\partial x} (a ln (x^{2} + y^{2}))

x \to 2 lim (2 x^{3} - 3 x^{2} + 4 x - 9)

What is the derivative of sqrt(x)+\sqrt[9]{x} ?
The derivative of sqrt(x)+\sqrt[9]{x} is 1/(2sqrt(x))+1/(9x^{8/9)}
What is the first derivative of sqrt(x)+\sqrt[9]{x} ?
The first derivative of sqrt(x)+\sqrt[9]{x} is 1/(2sqrt(x))+1/(9x^{8/9)}