What is the solution for (dy}{dx}-\frac{2x^3)/y =0 ?

The solution for (dy}{dx}-\frac{2x^3)/y =0 is y=sqrt(x^4+c_{1)},y=-sqrt(x^4+c_{1)}

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(dy}{dx}-\frac{2x^3)/y =0

\frac{d y}{d x} - \frac{2 x ^{3}}{y} = 0

y = x^{4} + c_{1}, y = - x^{4} + c_{1}

Solution steps

\frac{d y}{d x} - \frac{2 x ^{3}}{y} = 0

Solve separable ODE:

y = x^{4} + c_{1}, y = - x^{4} + c_{1}

y = x^{4} + c_{1}, y = - x^{4} + c_{1}

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\int \frac{1}{x ^{2} + 4 x - 12} d x

y^{^{''}} + 6 y^{^{'}} + 8 y = 0, y (0) = 9

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\frac{d}{d x} (\frac{9 x ^{2} - 6}{x ^{2}})

What is the solution for (dy}{dx}-\frac{2x^3)/y =0 ?
The solution for (dy}{dx}-\frac{2x^3)/y =0 is y=sqrt(x^4+c_{1)},y=-sqrt(x^4+c_{1)}