What is the derivative of 4cos(2x) ?

The derivative of 4cos(2x) is -8sin(2x)

What is the first derivative of 4cos(2x) ?

The first derivative of 4cos(2x) is -8sin(2x)

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derivative of

4 cos (2 x)

- 8 sin (2 x)

Solution steps

\frac{d}{d x} (4 cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 4 (- sin (2 x) \cdot 2)

Simplify

= - 8 sin (2 x)

\frac{d}{d x} ((x - 5) (x + 4) (x + 6))

\int_{0}^{2} x^{2} + 1 d x

(5.9) (- 4.6)

\frac{\partial}{\partial z} (x y e^{z})

y = x^{3} - 3 x + 2, (2, 4)

What is the derivative of 4cos(2x) ?
The derivative of 4cos(2x) is -8sin(2x)
What is the first derivative of 4cos(2x) ?
The first derivative of 4cos(2x) is -8sin(2x)