What is the tangent of f(x)= 7/x ,\at x=4 ?

The tangent of f(x)= 7/x ,\at x=4 is y=-7/16 x+7/2

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tangent of f(x)= 7/x ,\at x=4

tangent of

f (x) = \frac{7}{x}, at x = 4

y = - \frac{7}{16} x + \frac{7}{2}

Solution steps

Find the tangent point:

(4, \frac{7}{4})

Find the slope of

f (x) = \frac{7}{x} : \frac{df ( x )}{d x} = - \frac{7}{x ^{2}}

Compute the slope of

f (x) = \frac{7}{x}

x = 4 : m = - \frac{7}{16}

Find the line with slope m=

- \frac{7}{16}

and passing through

(4, \frac{7}{4}) : y = - \frac{7}{16} x + \frac{7}{2}

y = - \frac{7}{16} x + \frac{7}{2}

f (x) = ln (cos^{2} (x))

x \to 0 lim ((e^{x} + x)^{\frac{4}{x}})

\int 1 + x^{2} d x

n = 1 \sum \infty \frac{1}{( n ( n + 8 ) )}

\frac{d}{d x} (e^{- 6 x^{5}})

What is the tangent of f(x)= 7/x ,\at x=4 ?
The tangent of f(x)= 7/x ,\at x=4 is y=-7/16 x+7/2