What is the first derivative of-x^2+9 ?

The first derivative of-x^2+9 is -2x

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derivative of-x^2+9

\frac{d}{d x} (- x^{2} + 9)

- 2 x

Solution steps

\frac{d}{d x} (- x^{2} + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (9)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (9) = 0

= - 2 x + 0

Simplify

= - 2 x

\frac{7 e ^{x}}{( 7 + e ^{x} ) ^{2}}

\frac{d}{d t} (t^{r})

\int \frac{1}{x ^{2} + 10} d x

\int \frac{2}{- x ^{2} + 5} d x

\frac{s}{s ^{2} + 2 s + 4}