What is the tangent of 7/(x-2) ?

The tangent of 7/(x-2) is y=-7/((a_{0)-2)^2}x+(14a_{0}-14)/((a_{0)-2)^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 7/(x-2)

tangent of

\frac{7}{x - 2}

y = - \frac{7}{( a _{0} - 2 ) ^{2}} x + \frac{14 a _{0} - 14}{( a _{0} - 2 ) ^{2}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{7}{a _{0} - 2})

Find the slope of

y = \frac{7}{x - 2} : \frac{d y}{d x} = - \frac{7}{( x - 2 ) ^{2}}

Compute the slope of

y = \frac{7}{x - 2}

x = a_{0} : m = - \frac{7}{( a _{0} - 2 ) ^{2}}

Find the line with slope m=

- \frac{7}{( a _{0} - 2 ) ^{2}}

and passing through

(a_{0}, \frac{7}{a _{0} - 2}) : y = - \frac{7}{( a _{0} - 2 ) ^{2}} x + \frac{14 a _{0} - 14}{( a _{0} - 2 ) ^{2}}

y = - \frac{7}{( a _{0} - 2 ) ^{2}} x + \frac{14 a _{0} - 14}{( a _{0} - 2 ) ^{2}}

\int x i n^{2} x d x

\int \frac{x ^{2} - 81}{x ^{3}} d x

\int + \frac{x}{3 x ^{2} + 1} d x

\frac{d}{d x} ((2 x^{3} + 5)^{10})

\int sec (x) d x

What is the tangent of 7/(x-2) ?
The tangent of 7/(x-2) is y=-7/((a_{0)-2)^2}x+(14a_{0}-14)/((a_{0)-2)^2}