What is the derivative of rx+s ?

The derivative of rx+s is x(dr)/(dx)+r

What is the first derivative of rx+s ?

The first derivative of rx+s is x(dr)/(dx)+r

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\frac{d}{d x} (r x + s)

x \frac{d r}{d x} + r

Solution steps

\frac{d}{d x} (r x + s)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (r x) + \frac{d s}{d x}

\frac{d}{d x} (r x) = x \frac{d r}{d x} + r

\frac{d s}{d x} = 0

= x \frac{d r}{d x} + r + 0

Simplify

= x \frac{d r}{d x} + r

\int (2 x + 3)^{- 1} d x

\frac{d}{d s} (\frac{s - s}{s ^{2}})

3 - 2 x

\frac{d}{d x} ((2 x + 1)^{3} e^{- (1 - x)^{4}})

f (x) = \frac{1}{x + 6}

What is the derivative of rx+s ?
The derivative of rx+s is x(dr)/(dx)+r
What is the first derivative of rx+s ?
The first derivative of rx+s is x(dr)/(dx)+r