What is (\partial)/(\partial y)(2e^y+3sin(y)) ?

The answer to (\partial)/(\partial y)(2e^y+3sin(y)) is 2e^y+3cos(y)

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(\partial)/(\partial y)(2e^y+3sin(y))

\frac{\partial}{\partial y} (2 e^{y} + 3 sin (y))

2 e^{y} + 3 cos (y)

Solution steps

\frac{\partial}{\partial y} (2 e^{y} + 3 sin (y))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 e^{y}) + \frac{\partial}{\partial y} (3 sin (y))

\frac{\partial}{\partial y} (2 e^{y}) = 2 e^{y}

\frac{\partial}{\partial y} (3 sin (y)) = 3 cos (y)

= 2 e^{y} + 3 cos (y)

x^{2}, at x = 1

\frac{\partial}{\partial x} (\frac{1}{r ^{2}})

\int \frac{3}{e ^{5 x}} d x

f (x) = csc^{2} (x)

\int \frac{1}{1 - x} d x

What is (\partial)/(\partial y)(2e^y+3sin(y)) ?
The answer to (\partial)/(\partial y)(2e^y+3sin(y)) is 2e^y+3cos(y)