What is (\partial)/(\partial x)(3ln(x+y)-3x) ?

The answer to (\partial)/(\partial x)(3ln(x+y)-3x) is 3/(x+y)-3

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(\partial)/(\partial x)(3ln(x+y)-3x)

\frac{\partial}{\partial x} (3 ln (x + y) - 3 x)

\frac{3}{x + y} - 3

Solution steps

\frac{\partial}{\partial x} (3 ln (x + y) - 3 x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 ln (x + y)) - \frac{\partial}{\partial x} (3 x)

\frac{\partial}{\partial x} (3 ln (x + y)) = \frac{3}{x + y}

\frac{\partial}{\partial x} (3 x) = 3

= \frac{3}{x + y} - 3

n = 0 \sum \infty \frac{ln ( n )}{5 n}

π t + cos (\frac{4 π t + π}{2})

sin (3 t - \frac{1}{2})

x \to 0 lim (\frac{sin ^{4} ( x )}{x})

\frac{d}{d x} (2500 - x^{2})

What is (\partial)/(\partial x)(3ln(x+y)-3x) ?
The answer to (\partial)/(\partial x)(3ln(x+y)-3x) is 3/(x+y)-3