What is the integral from 1 to 27 of x^{1/3} ?

The integral from 1 to 27 of x^{1/3} is 60

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integral from 1 to 27 of x^{1/3}

\int_{1}^{27} x^{\frac{1}{3}} d x

60

Solution steps

\int_{1}^{27} x^{\frac{1}{3}} d x

Apply the Power Rule

: [\frac{3}{4} x^{\frac{4}{3}}]_{1}^{27}

= [\frac{3}{4} x^{\frac{4}{3}}]_{1}^{27}

Compute the boundaries:

60

= 60

\int - \frac{1}{3} (\frac{x}{3})^{n} d x

f (x) = 2 x^{3} + 8 x^{2} + 3 x + 3

\frac{d}{d x} (x^{4} - 5 x^{2} + 9)

\frac{\partial}{\partial x} (48 x^{3} cos (6 x^{2} y))

\frac{d}{d x} (\frac{x - 3}{x})

What is the integral from 1 to 27 of x^{1/3} ?
The integral from 1 to 27 of x^{1/3} is 60