What is the integral from 4 to infinity of e^{-x/3} ?

The integral from 4 to infinity of e^{-x/3} is 3/(e^{4/3)}

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integral from 4 to infinity of e^{-x/3}

\int_{4}^{\infty} e^{- \frac{x}{3}} d x

\frac{3}{e ^{\frac{4}{3}}}

Decimal Notation

0.79079 \dots

Solution steps

\int_{4}^{\infty} e^{- \frac{x}{3}} d x

Compute the indefinite integral:

\int e^{- \frac{x}{3}} d x = - 3 e^{- \frac{x}{3}} + C

Compute the boundaries:

\int_{4}^{\infty} e^{- \frac{x}{3}} d x = 0 - (- \frac{3}{e ^{\frac{4}{3}}})

= 0 - (- \frac{3}{e ^{\frac{4}{3}}})

Simplify

= \frac{3}{e ^{\frac{4}{3}}}

\int (2 x^{- 3} - 3 x^{2} - 2) d x

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\int \frac{1}{x 8 x + 9} d x

f (x) = \frac{3}{2 x - 1}, (1, 3)

What is the integral from 4 to infinity of e^{-x/3} ?
The integral from 4 to infinity of e^{-x/3} is 3/(e^{4/3)}