What is the solution for t^2y^{''}+15ty^'+49y=0 ?

The solution for t^2y^{''}+15ty^'+49y=0 is y=(c_{1})/(t^7)+(c_{2}ln(t))/(t^7)

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t^2y^{''}+15ty^'+49y=0

t^{2} y^{^{''}} + 15 t y^{^{'}} + 49 y = 0

y = \frac{c _{1}}{t ^{7}} + \frac{c _{2} ln ( t )}{t ^{7}}

Solution steps

t^{2} y^{''} (t) + 15 t y^{'} (t) + 49 y = 0

Solve linear ODE:

y = \frac{c _{1}}{t ^{7}} + \frac{c _{2} ln ( t )}{t ^{7}}

y = \frac{c _{1}}{t ^{7}} + \frac{c _{2} ln ( t )}{t ^{7}}

f (x) = cot (x) csc (x)

x \to \infty lim (8 ln (x))

6 x + 1

(x - 3)^{\frac{2}{3}}

x \to - 5 lim (4 x + 24)

What is the solution for t^2y^{''}+15ty^'+49y=0 ?
The solution for t^2y^{''}+15ty^'+49y=0 is y=(c_{1})/(t^7)+(c_{2}ln(t))/(t^7)