What is the solution for y^'=(6x)/y ?

The solution for y^'=(6x)/y is y=sqrt(6x^2+c_{1)},y=-sqrt(6x^2+c_{1)}

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y^'=(6x)/y

y^{^{'}} = \frac{6 x}{y}

y = 6 x^{2} + c_{1}, y = - 6 x^{2} + c_{1}

Solution steps

y^{'} (x) = \frac{6 x}{y}

Solve separable ODE:

y = 6 x^{2} + c_{1}, y = - 6 x^{2} + c_{1}

y = 6 x^{2} + c_{1}, y = - 6 x^{2} + c_{1}

\frac{d}{d y} ((\frac{1}{y ^{2}} - \frac{3}{y ^{4}}) (y + 5 y^{3}))

y^{^{''}} - y^{^{'}} - 2 y = 5 e^{- t}

\frac{d}{d x} (1 - x ln (x))

e^{2} t^{2}

What is the solution for y^'=(6x)/y ?
The solution for y^'=(6x)/y is y=sqrt(6x^2+c_{1)},y=-sqrt(6x^2+c_{1)}