What is the integral of 1/(a(sec(x))) ?

The integral of 1/(a(sec(x))) is 1/a sin(x)+C

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integral of 1/(a(sec(x)))

\int \frac{1}{a ( sec ( x ) )} d x

\frac{1}{a} sin (x) + C

Solution steps

\int \frac{1}{a sec ( x )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{a} \cdot \int \frac{1}{sec ( x )} d x

Rewrite using trig identities

= \frac{1}{a} \cdot \int cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= \frac{1}{a} sin (x)

Add a constant to the solution

= \frac{1}{a} sin (x) + C

\frac{d}{d x} (\frac{1 x + 1 + x}{x ^{2} - 1})

h

[x + (x + sin^{2} (x))^{4}]^{3}

\int_{2}^{7} (x^{2} - 2 x)^{2} d x

\int \frac{( x ^{3} - 2 x ^{2} + 7 x - 7 )}{x ^{2} - 2 x + 5} d x

What is the integral of 1/(a(sec(x))) ?
The integral of 1/(a(sec(x))) is 1/a sin(x)+C